Wednesday, May 29, 2019

C++ :: essays research papers

1. For each question below indicate True (T) or False (F)a. The binomial distribution is a potential model for a continuous variable Fb. In any normal distribution 95% of the probability lies within two standard deviations of the mean Tc. For a Poisson(m=4) distribution the variance is 2 Fd. For any exponential distribution, the mean is greater than the median Te. The Poisson is a good approximation to binomial when n is large and p is small. T(2+2+2+2+2=10 points)2. Given that the commonwealth under the standard normal curve, to the left of 2.3 is .0107, what is the areaunder the normal curve to the right of 2.3?(show give-up the ghost) DTDP ____0.0107____________value(8 points)3. Suppose you flip a fair coin 7 times, let X be the possible number of heads. Find the followingprobabilities (in each case show work below)(i) P(X = 0) =___(.5)7______________ (ii) P(X = 1) = __7*.5*.56_________(value) (value)(iii) Probability of at least 2 heads Prob. Statement _P(X 2)__ value __1-(.5 )7-7*(.5)7___(5+5+7+5=22 points)4. You are the safety inspector at some parts manufacturing plant. Safety at the plant is a concern it isknown that on an average there are 5 accidents per week. Assuming that the number of accidents inany week follows a Poisson distribution with mean 5, whats the probability that in 2 weeks there willbe only one accident? Let X be the number of accidents in 2 weeks.______P(X=1)________________ __10*e-10__________Prob. Statement value(show work Hint whats the distribution of X?)XPoisson(mean=2*5=10) (8+7=15 points)5. The scores on a test are normally distributed with a mean of 80 and a standard deviation of 5. Thescore distribution is shown in figure 1 below. Answer the following questions. Let X relate thevariable score.(a) Refer to the blue shaded area in figure 1. This is the probability of__P(X 70)______________ (just write the probability statement).(b) Find the value of probability in part (a) (show work)_P(Z

No comments:

Post a Comment

Note: Only a member of this blog may post a comment.